Condominium: Difference between revisions
Jump to navigation
Jump to search
Created page with "==Puzzle== In a certain condominium community, 2/3 of all the women are married and 3/5 of all the men are married. What fraction of the entire condominium community is marr..." |
Oscarlevin (talk | contribs) mNo edit summary |
||
| (2 intermediate revisions by 2 users not shown) | |||
| Line 1: | Line 1: | ||
==Puzzle== | ==Puzzle== | ||
In a certain condominium community, 2/3 of all the women are married and 3/5 of all the men are married. What fraction of the entire condominium community is married? | In a certain condominium community, 2/3 of all the women are married (to men) and 3/5 of all the men are married (to women). What fraction of the entire condominium community is married? | ||
{{Solution| The fraction of married women (M) to unmarried women (U) and the fraction of married men (M) to unmarried men (U) can be visualized as follows. | |||
MMMMMMUUU (Women) | |||
MMMMMMUUUU (Men) | |||
We know that the number of women who are married equals the number of men who are married. So the women’s M region and the men’s M region must be the same size. By using the same units in both the women’s diagram and the men’s diagram, we see that the two M regions are six units long each. This represents a total of 12 units out of a total possible of 19 units (9 from the women plus 10 from the men). So 12/19 of the condominium community is married.}} | |||
[[Category: Algebra]] | |||
Current revision as of 19:15, 4 April 2015
Puzzle
In a certain condominium community, 2/3 of all the women are married (to men) and 3/5 of all the men are married (to women). What fraction of the entire condominium community is married?
Solution